ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:26Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
302K
4β² + 5β + 0 = 0
d/dφ [φ^6] = 6φ^5
det| 5 7 ; 2 6 | = 16
17K
6n² + 3n + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
311K
CH₄ + 2O₂ → CO₂ + 2H₂O
264K
10β² + 6β + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
68K
det| 9 4 ; 1 10 | = 86
39K
F = ma
det| 12 1 ; 5 13 | = 151
6K
det| 10 8 ; 4 11 | = 78
det| 6 3 ; 7 7 | = 21