ChemCalc Dump /sym/7ed22d
id=26 · host=br.gridbatch.net · 2026-10-17 15:51Z
ω = 2πf
1y² + 6y + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{4}{1} \sum_{i=1}^{n} i^{2}
133K
CH₄ + 2O₂ → CO₂ + 2H₂O
177K
1t² + 9t + 7 = 0
\lim_{n\to 0} \frac{\sin n}{n} = 1
45K
7t² + 2t + 2 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
437K
∑_{k=1}^{n} k = n(n+1)/2
115K
\frac{7}{4} \sum_{i=1}^{n} i^{2}
364K
CH₄ + 2O₂ → CO₂ + 2H₂O
238K
det| 12 2 ; 5 13 | = 146
7K
det| 5 5 ; 3 6 | = 15
30K