ChemCalc Dump /sym/24b7a5
id=28 · host=br.gridbatch.net · 2026-10-17 15:48Z
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
93K
det| 7 3 ; 6 8 | = 38
211K
5z² + 5z + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
311K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
453K
F = ma
∫₀^∞ e^(-ψ²) dψ = √π / 2
133K
2φ² + 9φ + 6 = 0
det| 9 2 ; 3 10 | = 84
437K
det| 11 3 ; 5 12 | = 117
115K