ref 2a17e2bb
ChemCalc Dump /sym/d8aa7c
id=23 · host=br.gridbatch.net · 2026-08-16 21:49Z
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
184K
\oint_C \vec{F}\cdot d\vec{r} = 0
479K
10r² + 3r + 3 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
287K
\lim_{r\to 0} \frac{\sin r}{r} = 1
e^{i\pi} + 1 = 0
det| 4 3 ; 2 5 | = 14
det| 9 5 ; 1 10 | = 85
det| 11 3 ; 1 12 | = 129
\lim_{β\to 0} \frac{\sin β}{β} = 1
F = ma
λ = h/p