ChemCalc Dump /sym/c0a0b3
id=24 · host=br.gridbatch.net · 2026-10-17 15:52Z
\frac{3}{9} \sum_{i=1}^{n} i^{2}
E = mc²
det| 2 3 ; 0 3 | = 6
453K
det| 4 9 ; 2 5 | = 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
177K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-z²) dz = √π / 2
207K
∑_{k=1}^{n} k = n(n+1)/2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
333K
det| 2 7 ; 2 3 | = -8
437K
det| 1 7 ; 2 2 | = -12
115K
\frac{4}{5} \sum_{i=1}^{n} i^{2}
238K
det| 4 9 ; 3 5 | = -7
111K
CH₄ + 2O₂ → CO₂ + 2H₂O
267K