ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:24Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
d/dz [z^11] = 11z^10
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∫₀^∞ e^(-r²) dr = √π / 2
∫₀^∞ e^(-ψ²) dψ = √π / 2
125K
12γ² + 2γ + 2 = 0
det| 9 4 ; 1 10 | = 86
310K
E = mc²
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
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det| 7 1 ; 7 8 | = 49
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t