ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:53Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
17K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
311K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
364K