ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 22:42Z
\frac{7}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
312K
CaCO₃ → CaO + CO₂
8t² + 2t + 1 = 0
d/dφ [φ^12] = 12φ^11
det| 5 6 ; 4 6 | = 6
311K
E = mc²
det| 7 4 ; 4 8 | = 40
68K
10r² + 8r + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2