ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:22Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 1 ; 7 8 | = 49
302K
4β² + 5β + 0 = 0
d/dφ [φ^6] = 6φ^5
det| 4 8 ; 0 5 | = 20
17K
CH₄ + 2O₂ → CO₂ + 2H₂O
310K
6n² + 3n + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
264K
10β² + 6β + 6 = 0
F = ma