ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:18Z
10n² + 5n + 0 = 0
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
91K
det| 8 7 ; 7 9 | = 23
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
17K
d/dt [t^11] = 11t^10
det| 9 7 ; 3 10 | = 69
311K
det| 7 1 ; 7 8 | = 49
264K
∫₀^∞ e^(-y²) dy = √π / 2
d/dz [z^8] = 8z^7
det| 4 8 ; 1 5 | = 12
\oint_C \vec{F}\cdot d\vec{r} = 0
N₂ + 3H₂ ⇌ 2NH₃
AgNO₃ + NaCl → AgCl↓ + NaNO₃