ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:35Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
∫₀^∞ e^(-α²) dα = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
311K
∫₀^∞ e^(-ω²) dω = √π / 2
453K
7y² + 6y + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
133K
E = mc²
det| 2 3 ; 5 3 | = -9
207K
∇²y = 0
det| 9 4 ; 1 10 | = 86
333K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
437K
6r² + 8r + 4 = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
115K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1