ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:03Z
∑_{k=1}^{n} k = n(n+1)/2
4β² + 5β + 0 = 0
det| 9 5 ; 1 10 | = 85
91K
d/dφ [φ^6] = 6φ^5
6n² + 3n + 0 = 0
det| 5 7 ; 2 6 | = 16
311K
det| 8 4 ; 6 9 | = 48
264K
10β² + 6β + 6 = 0
det| 7 4 ; 4 8 | = 40
68K