ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:02Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
302K
4β² + 5β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
d/dφ [φ^6] = 6φ^5
det| 7 1 ; 7 8 | = 49
17K
det| 3 7 ; 2 4 | = -2
310K
6n² + 3n + 0 = 0
det| 9 4 ; 1 10 | = 86
264K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
68K