ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:57Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
17K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
2H₂ + O₂ → 2H₂O
det| 9 4 ; 1 10 | = 86
68K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
39K
10r² + 7r + 5 = 0
e^{i\pi} + 1 = 0