ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 02:01Z
4α² + 9α + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
302K
∫₀^∞ e^(-t²) dt = √π / 2
312K
∫₀^∞ e^(-y²) dy = √π / 2
det| 9 2 ; 3 10 | = 84
91K
det| 1 9 ; 6 2 | = -52
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
311K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
364K