ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 17:21Z
∫₀^∞ e^(-φ²) dφ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
257K
det| 10 2 ; 5 11 | = 100
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
159K
PV = nRT
∫₀^∞ e^(-x²) dx = √π / 2
437K
7y² + 8y + 2 = 0
9n² + 7n + 4 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
202K
CH₄ + 2O₂ → CO₂ + 2H₂O
CH₄ + 2O₂ → CO₂ + 2H₂O
479K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{1}{5} \sum_{i=1}^{n} i^{2}
e^{i\pi} + 1 = 0