ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:26Z
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
302K
12φ² + 6φ + 4 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
91K
2H₂ + O₂ → 2H₂O
det| 1 2 ; 7 2 | = -12
310K
5φ² + 5φ + 0 = 0
\frac{6}{3} \sum_{i=1}^{n} i^{2}
311K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
264K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
39K
ΔS ≥ 0
det| 6 6 ; 3 7 | = 24
364K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
6K