ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
d/dz [z^11] = 11z^10
312K
12φ² + 6φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
det| 5 9 ; 7 6 | = -33
91K
2H₂ + O₂ → 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂
17K
5φ² + 5φ + 0 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
39K
det| 9 8 ; 3 10 | = 66
364K