ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:23Z
iħ ∂ψ/∂t = Ĥψ
∫₀^∞ e^(-x²) dx = √π / 2
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
AgNO₃ + NaCl → AgCl↓ + NaNO₃
270K
∇²t = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 7 ; 4 8 | = 28
231K
5ω² + 9ω + 6 = 0
∫₀^∞ e^(-α²) dα = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃