ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:47Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
302K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
312K
∇²ω = 0
det| 7 1 ; 7 8 | = 49
91K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
17K
det| 1 8 ; 4 2 | = -30
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Fe₂O₃ + 3CO → 2Fe + 3CO₂
311K
det| 5 2 ; 3 6 | = 24
264K
2H₂ + O₂ → 2H₂O
10r² + 7r + 5 = 0
det| 10 4 ; 1 11 | = 106
364K