ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:30Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
∫₀^∞ e^(-α²) dα = √π / 2
\frac{2}{2} \sum_{i=1}^{n} i^{2}
311K
det| 9 4 ; 1 10 | = 86
453K
7y² + 6y + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
133K
∑_{k=1}^{n} k = n(n+1)/2
177K
E = mc²
\frac{6}{3} \sum_{i=1}^{n} i^{2}
45K
∇²y = 0
det| 12 1 ; 5 13 | = 151
333K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
6r² + 8r + 4 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-β²) dβ = √π / 2