ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:26Z
N₂ + 3H₂ ⇌ 2NH₃
det| 4 8 ; 0 5 | = 20
302K
det| 9 4 ; 1 10 | = 86
312K
12φ² + 6φ + 4 = 0
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
17K
5φ² + 5φ + 0 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
68K