ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:46Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
\frac{4}{6} \sum_{i=1}^{n} i^{2}
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 4 8 ; 0 5 | = 20
17K
det| 10 4 ; 1 11 | = 106
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
10r² + 7r + 5 = 0
e^{i\pi} + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃