ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:31Z
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
259K
det| 1 4 ; 2 2 | = -6
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 11 5 ; 0 12 | = 132
270K
∇²t = 0
det| 1 4 ; 3 2 | = -10
193K
∫₀^∞ e^(-ψ²) dψ = √π / 2
202K