ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:40Z
7φ² + 7φ + 6 = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
AgNO₃ + NaCl → AgCl↓ + NaNO₃
125K
9n² + 8n + 4 = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
310K
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
311K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃