ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:58Z
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
302K
4β² + 5β + 0 = 0
det| 9 8 ; 3 10 | = 66
125K
∑_{k=1}^{n} k = n(n+1)/2
91K
d/dφ [φ^6] = 6φ^5
det| 7 4 ; 4 8 | = 40
310K
det| 1 4 ; 3 2 | = -10
311K
det| 11 5 ; 0 12 | = 132
264K
∑_{k=1}^{n} k = n(n+1)/2
68K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
39K