ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-β²) dβ = √π / 2
302K
det| 5 9 ; 7 6 | = -33
312K
12φ² + 6φ + 4 = 0
2H₂ + O₂ → 2H₂O
5φ² + 5φ + 0 = 0
∫₀^∞ e^(-t²) dt = √π / 2
311K
det| 5 3 ; 2 6 | = 24
264K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
ΔS ≥ 0