ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:55Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\frac{6}{3} \sum_{i=1}^{n} i^{2}
311K
2H₂ + O₂ → 2H₂O
\lim_{x\to 0} \frac{\sin x}{x} = 1
68K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
39K
10r² + 7r + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
6K