ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:12Z
iħ ∂ψ/∂t = Ĥψ
det| 7 4 ; 4 8 | = 40
259K
∑_{k=1}^{n} k = n(n+1)/2
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
437K
det| 2 7 ; 7 3 | = -43
442K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
231K