ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:05Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
312K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-ω²) dω = √π / 2
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\frac{6}{3} \sum_{i=1}^{n} i^{2}
311K
det| 7 4 ; 4 8 | = 40
264K
2H₂ + O₂ → 2H₂O
iħ ∂ψ/∂t = Ĥψ