ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:40Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
302K
det| 5 6 ; 1 6 | = 24
312K
∫₀^∞ e^(-r²) dr = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
91K
12γ² + 2γ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
17K
E = mc²
λ = h/p
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}