ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:47Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 9 ; 7 6 | = -33
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∇²ω = 0
det| 7 4 ; 4 8 | = 40
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-x²) dx = √π / 2
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\frac{2}{2} \sum_{i=1}^{n} i^{2}
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