ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:35Z
10n² + 5n + 0 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
302K
∑_{k=1}^{n} k = n(n+1)/2
312K
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
91K
det| 8 7 ; 7 9 | = 23
det| 7 4 ; 4 8 | = 40
310K
d/dt [t^11] = 11t^10
det| 9 7 ; 3 10 | = 69
311K
∫₀^∞ e^(-y²) dy = √π / 2
det| 4 8 ; 1 5 | = 12
\binom{n}{k} = \frac{n!}{k!(n-k)!}
364K
\oint_C \vec{F}\cdot d\vec{r} = 0
N₂ + 3H₂ ⇌ 2NH₃
AgNO₃ + NaCl → AgCl↓ + NaNO₃