ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:31Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
∫₀^∞ e^(-α²) dα = √π / 2
7y² + 6y + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
133K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
177K
E = mc²
det| 9 7 ; 3 10 | = 69
45K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
207K
∇²y = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
6r² + 8r + 4 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-β²) dβ = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂