ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-z²) dz = √π / 2
312K
12φ² + 6φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
2H₂ + O₂ → 2H₂O
5φ² + 5φ + 0 = 0
det| 9 4 ; 1 10 | = 86
264K
det| 9 5 ; 6 10 | = 60
68K
det| 11 9 ; 5 12 | = 87
39K