ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:06Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
∫₀^∞ e^(-n²) dn = √π / 2
91K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 4 ; 4 8 | = 40
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
311K
2H₂ + O₂ → 2H₂O
\frac{8}{6} \sum_{i=1}^{n} i^{2}
68K
10r² + 7r + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
364K
e^{i\pi} + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
λ = h/p