ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:57Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∇²ω = 0
det| 2 7 ; 7 3 | = -43
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det| 11 9 ; 0 12 | = 132
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{11}{6} \sum_{i=1}^{n} i^{2}
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\frac{2}{2} \sum_{i=1}^{n} i^{2}
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