ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:44Z
iħ ∂ψ/∂t = Ĥψ
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\lim_{t\to 0} \frac{\sin t}{t} = 1
∇²t = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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5ω² + 9ω + 6 = 0