ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:53Z
7φ² + 7φ + 6 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 9 8 ; 3 10 | = 66
91K
9n² + 8n + 4 = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
310K
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
311K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 5 ; 0 6 | = 30
det| 3 5 ; 7 4 | = -23
F = ma
∇²y = 0