ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:21Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-r²) dr = √π / 2
det| 9 5 ; 6 10 | = 60
125K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
91K
12γ² + 2γ + 2 = 0
E = mc²
det| 4 6 ; 0 5 | = 20
311K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
264K
λ = h/p
det| 10 9 ; 0 11 | = 110
39K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t