ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:39Z
7φ² + 7φ + 6 = 0
det| 7 4 ; 4 8 | = 40
302K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 7 1 ; 7 8 | = 49
125K
9n² + 8n + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
17K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
311K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃