ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:54Z
∑_{k=1}^{n} k = n(n+1)/2
spec_5686.mol
∑_{k=1}^{n} k = n(n+1)/2
302K
eq_9425.csv
e^{i\pi} + 1 = 0
312K
4β² + 5β + 0 = 0
ops_6502.csv
∇ × E = −∂B/∂t
125K
spec_7724.csv
d/dt [t^3] = 3t^2
91K
d/dφ [φ^6] = 6φ^5
spec_4768.mol
∑_{k=1}^{n} k = n(n+1)/2
17K
rxn_0414.log
det| 9 4 ; 1 10 | = 86
310K
eq_7548.json
det| 3 7 ; 2 4 | = -2
311K
rxn_7658.eqn
2β² + 9β + 3 = 0
264K
[
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
]
Σ#12
Matrix 23
Rxn set 2
Batch 4
Batch 28
Rxn set 26
Ledger /15
Eq pack 13
Matrix 11
Eq pack 1
Batch 22
Matrix 17
Ledger /21
Eq pack 25
Rxn set 20