ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:25Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-r²) dr = √π / 2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
125K
∫₀^∞ e^(-x²) dx = √π / 2
91K
12γ² + 2γ + 2 = 0
E = mc²
λ = h/p
det| 5 6 ; 1 6 | = 24
68K
det| 4 8 ; 0 5 | = 20
39K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}