ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:47Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-z²) dz = √π / 2
312K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
17K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 7 7 ; 4 8 | = 28
364K