ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:25Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{8}{6} \sum_{i=1}^{n} i^{2}
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∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
E = mc²
λ = h/p
det| 5 6 ; 1 6 | = 24
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
det| 12 9 ; 5 13 | = 111
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O