ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:21Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
302K
∫₀^∞ e^(-r²) dr = √π / 2
det| 7 4 ; 4 8 | = 40
91K
12γ² + 2γ + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
17K
E = mc²
det| 9 8 ; 3 10 | = 66
311K
λ = h/p
det| 4 6 ; 0 5 | = 20
39K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}