ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:56Z
7φ² + 7φ + 6 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\frac{6}{3} \sum_{i=1}^{n} i^{2}
91K
9n² + 8n + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
ΔS ≥ 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
311K
E = mc²
det| 11 9 ; 0 12 | = 132
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃