ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:41Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-r²) dr = √π / 2
det| 5 3 ; 2 6 | = 24
125K
12γ² + 2γ + 2 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
E = mc²
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O