ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:17Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
302K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
312K
∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
311K
λ = h/p
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}