ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:27Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
302K
∫₀^∞ e^(-r²) dr = √π / 2
∫₀^∞ e^(-n²) dn = √π / 2
91K
12γ² + 2γ + 2 = 0
E = mc²
det| 5 7 ; 2 6 | = 16
264K
λ = h/p
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\oint_C \vec{F}\cdot d\vec{r} = 0
364K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O